ppm is an abbreviation of parts per million. ppm is a value that represents the part of a whole number in units of 1/1000000.
ppm is dimensionless quantity, a ratio of 2 quantities of the same unit. For example: mg/kg.
One ppm is equal to 1/1000000 of the whole:
1ppm = 1/1000000 = 0.000001 = 1×10-6
One ppm is equal to 0.0001%:
1ppm = 0.0001%
ppmw is an abbreviation of parts per million weight, a subunit of ppm that is used for part of weights like milligrams per kilogram (mg/kg).
ppmv is an abbreviation of parts per million volume, a subunit of ppm that is used for part of volumes like milliliters per cubic meter (ml/m3).
Other part-per notations are written here:
Name | Notation | Coefficient |
---|---|---|
Percent | % | 10-2 |
Per-mille | ‰ | 10-3 |
Parts per million | ppm | 10-6 |
Parts per billion | ppb | 10-9 |
Parts per trillion | ppt | 10-12 |
ppm is used to measure chemical concentration, usually in a solution of water.
Solute concentration of 1 ppm is solute concentration of 1/1000000 of the solution.
The concentration C in ppm is calculated from the solute mass msolute in milligrams and the solution mass msolution in milligrams .
C(ppm) = 1000000 × msolute / (msolution + msolute)
Usually the solute mass msolute is much smaller than the solution mass msolution.
msolute ≪ msolution
Then the concentration C in ppm is equal to 1000000 times the solute mass msolute in milligrams (mg) divided by the solution mass msolution in milligrams (mg):
C(ppm) = 1000000 × msolute (mg) / msolution (mg)
The concentration C in ppm is also equal to the solute mass msolute in milligrams (mg) divided by the solution mass msolution in kilograms (kg):
C(ppm) = msolute (mg) / msolution (kg)
When the solution is water, the volume of mass of one kilogram is approximately one liter.
The concentration C in ppm is also equal to the solute mass msolute in milligrams (mg) divided by the water solution volume Vsolution in liters (l):
C(ppm) = msolute (mg) / Vsolution (l)
The concentration of carbon dioxide (CO2) in the atmosphere is about 388ppm.
The frequency stability of an electronic oscillator component can be measured in ppm.
The maximal frequency variation Δf, divided by the frequency f is equal to the frequency stability
Δf(Hz) / f(Hz) = FS(ppm) / 1000000
Oscillator with frequency of 32MHz and accuracy of ±200ppm, has frequency accuracy of
Δf(Hz) = ±200ppm × 32MHz / 1000000 = ±6.4kHz
So the oscillator produces clock signal within the range of 32MHz±6.4kHz.
The supplied frequency variation is caused from temperature change, aging, supply voltage and load changes.
Enter proportion part in one of the text boxes and press the Convert button:
Water solution, molar concentration (molarity) to milligrams per liter to parts per million (ppm) converter.
The part P in decimal is equal to the part P in ppm divided by 1000000:
P(decimal) = P(ppm) / 1000000
Find the decimal fraction of 300ppm:
P(decimal) = 300ppm / 1000000 = 0.0003
The part P in ppm is equal to the part P in decimal times 1000000:
P(ppm) = P(decimal) × 1000000
Find how many ppm are in 0.0034:
P(ppm) = 0.0034 × 1000000 = 3400ppm
The part P in percent (%) is equal to the part P in ppm divided by 10000:
P(%) = P(ppm) / 10000
Find how many percent are in 6ppm:
P(%) = 6ppm / 10000 = 0.0006%
The part P in ppm is equal to the part P in percent (%) times 10000:
P(ppm) = P(%) × 10000
Find how many ppm are in 6%:
P(ppm) = 6% × 10000 = 60000ppm
The part P in ppm is equal to the part P in ppb divided by 1000:
P(ppm) = P(ppb) / 1000
Find how many ppm are in 6ppb:
P(ppm) = 6ppb / 1000 = 0.006ppm
The part P in ppb is equal to the part P in ppm times 1000:
P(ppb) = P(ppm) × 1000
Find how many ppb are in 6ppm:
P(ppb) = 6ppm × 1000 = 6000ppb
The concentration C in parts-per million (ppm) is equal to the concentration C in milligrams per kilogram (mg/kg) and equal to 1000 times the concentration C in milligrams per liter (mg/L), divided by the solution density ρ in kilograms per cubic meter (kg/m3):
C(ppm) = C(mg/kg) = 1000 × C(mg/L) / ρ(kg/m3)
In water solution, the concentration C in parts-per million (ppm) is equal to 1000 times the concentration C in milligrams per liter (mg/L) divided by the water solution density at temperature of 20ºC, 998.2071 in kilograms per cubic meter (kg/m3) and approximately equal to the concentration C in milligrams per liter (mg/L):
C(ppm) = 1000 × C(mg/L) / 998.2071(kg/m3) ≈ 1(L/kg) × C(mg/L)
The concentration C in parts-per million (ppm) is equal to 1000 times the concentration C in grams per kilogram (g/kg) and equal to 1000000 times the concentration C in grams per liter (g/L), divided by the solution density ρ in kilograms per cubic meter (kg/m3):
C(ppm) = 1000 × C(g/kg) = 106 × C(g/L) / ρ(kg/m3)
In water solution, the concentration C in parts-per million (ppm) is equal to 1000 times the concentration C in grams per kilogram (g/kg) and equal to 1000000 times the concentration C in grams per liter (g/L), divided by the water solution density at temperature of 20ºC 998.2071 in kilograms per cubic meter (kg/m3) and approximately equal to 1000 times the concentration C in milligrams per liter (mg/L):
C(ppm) = 1000 × C(g/kg) = 106 × C(g/L) / 998.2071(kg/m3) ≈ 1000 × C(g/L)
The concentration C in parts-per million (ppm) is equal to the concentration C in milligrams per kilogram (mg/kg) and equal to 1000000 times the molar concentration (molarity) c in moles per liter (mol/L), times the solute molar mass in grams per mole (g/mol), divided by the solution density ρ in kilograms per cubic meter (kg/m3):
C(ppm) = C(mg/kg) = 106 × c(mol/L) × M(g/mol) / ρ(kg/m3)
In water solution, the concentration C in parts-per million (ppm) is equal to the concentration C in milligrams per kilogram (mg/kg) and equal to 1000000 times the molar concentration (molarity) c in moles per liter (mol/L), times the solute molar mass in grams per mole (g/mol), divided by the water solution density at temperature of 20ºC 998.2071 in kilograms per cubic meter (kg/m3):
C(ppm) = C(mg/kg) = 106 × c(mol/L) × M(g/mol) / 998.2071(kg/m3) ≈ 1000 × c(mol/L) × M(g/mol)
The frequency variation in hertz (Hz) is equal to the frequency stability FS in ppm times the frequency in hertz (Hz) divided by 1000000:
Δf(Hz) = ± FS(ppm) × f(Hz) / 1000000
Oscillator with frequency of 32MHz and accuracy of ±200ppm, has frequency accu0racy of
Δf(Hz) = ±200ppm × 32MHz / 1000000 = ±6.4kHz
So the oscillator produces clock signal within the range of 32MHz±6.4kHz.
Parts-per million (ppm) | Coefficient / Ratio | Percent (%) | Parts per billion (ppb) | Parts per trillion (ppt) |
---|---|---|---|---|
1 ppm | 1×10-6 | 0.0001% | 1000 ppb | 1×106 ppt |
2 ppm | 2×10-6 | 0.0002% | 2000 ppb | 2×106 ppt |
3 ppm | 3×10-6 | 0.0003% | 3000 ppb | 3×106 ppt |
4 ppm | 4×10-6 | 0.0004% | 4000 ppb | 4×106 ppt |
5 ppm | 5×10-6 | 0.0005% | 5000 ppb | 5×106 ppt |
6 ppm | 6×10-6 | 0.0006% | 6000 ppb | 6×106 ppt |
7 ppm | 7×10-6 | 0.0007% | 7000 ppb | 7×106 ppt |
8 ppm | 8×10-6 | 0.0008% | 8000 ppb | 8×106 ppt |
9 ppm | 9×10-6 | 0.0009% | 9000 ppb | 9×106 ppt |
10 ppm | 1×10-5 | 0.0010% | 10000 ppb | 1×107 ppt |
20 ppm | 2×10-5 | 0.0020% | 20000 ppb | 2×107 ppt |
30 ppm | 3×10-5 | 0.0030% | 30000 ppb | 3×107 ppt |
40 ppm | 4×10-5 | 0.0040% | 40000 ppb | 4×107 ppt |
50 ppm | 5×10-5 | 0.0050% | 50000 ppb | 5×107 ppt |
60 ppm | 6×10-5 | 0.0060% | 60000 ppb | 6×107 ppt |
70 ppm | 7×10-5 | 0.0070% | 70000 ppb | 7×107 ppt |
80 ppm | 8×10-5 | 0.0080% | 80000 ppb | 8×107 ppt |
90 ppm | 9×10-5 | 0.0090% | 90000 ppb | 9×107 ppt |
100 ppm | 1×10-4 | 0.0100% | 100000 ppb | 01×108 ppt |
200 ppm | 2×10-4 | 0.0200% | 200000 ppb | 2×108 ppt |
300 ppm | 3×10-4 | 0.0300% | 300000 ppb | 3×108 ppt |
400 ppm | 4×10-4 | 0.0400% | 400000 ppb | 4×108 ppt |
500 ppm | 5×10-4 | 0.0500% | 500000 ppb | 5×108 ppt |
1000 ppm | 0.001 | 0.1000% | 1×106 ppb | 1×109 ppt |
10000 ppm | 0.010 | 1.0000% | 1×107 ppb | 1×1010 ppt |
100000 ppm | 0.100 | 10.0000% | 1×108 ppb | 1×1011 ppt |
1000000 ppm | 1.000 | 100.0000% | 1×109 ppb | 1×1012 ppt |